Robert P. Munafo, 2011 Feb 27.

The "period" as used in this glossary is the number of points in a limit cycle. See also Orbit Detection.

Period is defined only for points that have a limit cycle. The rest of this discussion will assume that the Mandelbrot Set is the iterative process in question (see iteration for the definition of the iteration function).

Periods in Iteration

For the Mandelbrot Set, all points in the interior have a period. The mu-atoms each have a specific period, and all points in the mu-atom have that period. Thus one can refer to "the period of a mu-atom".

For example, consider the point -1 + 0i. Applying the iteration algorithm we get:

Z0 = 0 + 0i
Z1 = -1 + 0i
Z2 = 0 + 0i
Z3 = -1 + 0i
Z4 = 0 + 0i

Because the values of Zn repeat in a continuous cycle of two values, the point is said to have a period of 2. The points -1+0i and 0+0i together constitute the point's limit cycle.

If C is a point fairly close to this (such as -1.07+0.11i) then the values of Z1, Z2, Z3, etc. will be somewhat different, but they will still be close to the values in the example. Furthermore, as n gets larger, the values of Zn will get closer and closer to a pair of values that alternate, just like in the example — a 2-element limit cycle.

Finding the Period of a mu-Atom

If the approximate location and size of a mu-atom are known, its period can be found using the following method, which is similar to the Synchronous-Orbit Algorithm.

1. Identify a polygon with at least three vertices, such that the nucleus is known to be inside the polygon. (In practice, a square is the simplest polygon to use.)

2. Define values of Ci for each vertex, and set initial values of Zi=0. Then, iterate Zi2+Ci for all values of Zi, one step at a time.

3. At each iteration step, count how many edges of the polygon cross the positive half of the real axis. (Actually, either half of either axis will work). If an odd number of edges cross the positive real axis, then we know the origin is inside the polygon. (This method works because of the Jordan Curve Theorem.)

4. Look and see how many iterations you had to do to get to the set of vertices that contains the origin. This is the period.

5. This method will find the lowest period within the starting polygon. Therefore, if the location of the nucleus is known only approximately, the method will still work.

An Example

For example, we want to find the period of the cardioid that is part of the mu-molecule R2F(1/3B1)S. By viewing (see here for a picture) we know it is somewhere in the vicinity of -0.158 + 1.033i, and is clearly contained within a square 0.030 units long on each side centered at that point. Therefore, we can use -0.158±0.015 for the real, and 1.033±0.015 for the imaginary coordinates of the vertices of a square (roughly corresponding to the corners of the picture on the R2F(1/3B1)S page) and assign these to C0 through C3. Iteration proceeds as follows:

iteration Z0 Z1 Z2 Z3
0 0 0 0 0
1 -0.173+1.018i -0.143+1.018i -0.143+1.048i -0.173+1.048i
2 -1.179+0.666i -1.159+0.727i -1.221+0.748i -1.241+0.685i
3 0.775-0.552i 0.672-0.667i 0.788-0.779i 0.898-0.654i
4 0.122+0.162i -0.136+0.122i -0.130-0.179i 0.207-0.126i

As always (see Iterates) iteration 0 is 0, and iteration 1 is the parameter Ci. We can see pretty easily that for iteration 2, all the points are way off to the upper-left somewhere, and for iteration 3, they're all to the lower right.

The Main Insight

For iteration 4, you can see (using graph paper if necessary) that the line segment connecting Z0 and Z3 crosses the positive half of the real axis, and that none of the others do. Imagine traveling from Z0 to Z3, then to Z2, then to Z1, then back to Z0. This is a closed path tracing out the boundary of a quadrilateral. Since only one of the four edges (the edge from Z0 to Z3) crosses the positive half of the real axis, the path must surround the origin. In other words, we can say that "the 4th iteration of the original square surrounds the origin". That means1 that somewhere within the original square is a point whose 4th iteration falls exactly on the origin, and that point has period 4.

This method works because the function Z2+C is continuous, and because the origin 0+0i is always part of the limit cycle of any attractive periodic point. (It does not work for repelling periodic points such as the terminal point 0+i.)

Although a period has been found, this algorithm alone does not guarantee that there is an island. It might be a Misiurewicz point like 0+i (which has period 2).

The method can even be used to (approximately) find the location of the mu-atom's nucleus. The location of the origin within the iterated polygon corresponds to the location of the original point within the original square. Linear interpolation gives an inexact answer, because the iteration function is not linear. However, making a small adjustment to the polygon, repeating the algorithm, and iterating can often find the exact location of the nucleus.

Other Methods

There are also methods of finding the period of a point without knowing the location of the mu-atom containing it. For example, one can iterate a "whole lot" of times, then see if the last iteration equals any of the previous iterations.

However, such methods are never foolproof. Typically, they fail when used on points that are comparatively close to the boundary of their mu-atom. In such cases the algorithm will usually "find" an integer multiple of the actual period. This happens because as you get close to a child mu-atom, the points approaching the limit cycle converge in a spiral or pinheel-like manner. For example, imagine the period is actually 5, and our point is close to a child mu-atom with period 35. If you look at each 5th iterate, you'll typically find a pattern that spirals in on a limit point, taking 7 steps to go each time around the spiral. Because of the spiral pattern, the 7th step (35th iteration) is a lot closer than the 1st step (5th iteration), and simple period-finding algorithms will catch the closer one.

Repelling Periods

As just mentioned above, there are points whose iterates have a period, but the point itself is not part of the limit cycle. These are "repelling" periodic points because all nearby points either escape, iterate chaotically, or have some other period. An example of such a point is 0+i:

Z0 = 0
Z1 = 0 + i
Z2 = -1 + i
Z3 = 0 - i
Z4 = -1 + i
Z5 = 0 - i

With points like this you will only find a period if you start with the precise coordinates of the periodic point and if there is no roundoff error. Here is the same iteration for 0.001 + i:

Z0 = 0.00000
Z1 = +0.00100 + 1.00000 i
Z2 = -0.99900 + 1.00200 i
Z3 = -0.00500 - 1.00200 i
Z4 = -1.00297 + 1.01003 i
Z5 = -0.01322 - 1.02605 i
Z6 = -1.05161 + 1.02712 i
Z7 = +0.05190 - 1.16027 i

These iterates drift away from the limit cycle [-1+i, 0-i] at an exponentially increasing rate. By Z11 = -2.62645 + 3.86102i the iteration has escaped.

Displaying Period Information

Views that display the periods of mu-atoms (usually in some color-coded way) are fairly enlightening, because they show important relationships between the periods of nearby mu-atoms. For example, children belonging to a mu-atom all have periods that are multiples of the parent's period. See representation functions.

This page has a nice picture showing mu-atoms in different colors.


1 : somewhere within : This fact is related to the Jordan curve theorem, and the fact that the function Z2+C has no Branch points.

revisions: 20080309 oldest on record; 20100825 add spiral divergence (0.001+i) example; 20110227 clarify Jordan curve argument

From the Mandelbrot Set Glossary and Encyclopedia, by Robert Munafo, (c) 1987-2017.     Mu-ency index

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