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2.5063 - RIES (RILYBOT Inverse Equation Solver)    

RIES command: ./ries --wide -l1 -s 2.5063 Your target value: T = 2.5063 mrob.com/ries

equation root of equation distance from your target accurate to within complexity
x = 5/2
x = 2.5 = T - 0.0063 1 part in 398 50
x = e^3/8
x = 2.51069211539846 = T + 0.00439212 1 part in 571 67
x = sqrt(2 pi)
x = 2.506628274631 = T + 0.000328275 1 part in 7635 55
x = xⁿ√(1+9)
x = 2.50618414558877 = T - 0.000115854 1 part in 21633 70
x = sqrt(9-e)
x = 2.50633560632669 = T + 3.56063e-05 1 part in 70389 64
x = (sqrt(pi)+e)/ln(6)
x = 2.5063273036862 = T + 2.73037e-05 1 part in 91793 94
x = 4(4ⁿ√7-1)
x = 2.50630624679114 = T + 6.24679e-06 1 part in 401214 91
sinpi(ln(x)) = sqrt(1/(5 pi))
x = 2.50630275664667 = T + 2.75665e-06 1 part in 909184 92
x = (e^-(phi/3)+1)^2
x = 2.50630146469868 = T + 1.4647e-06 1 part in 1711137 96
cospi(1/(x+2)) = sqrt(sinpi(1/5))
x = 2.50630091552832 = T + 9.15528e-07 1 part in 2737545 98
tanpi(1/x) = (5^2)ⁿ√3+2
x = 2.50629971692242 = T - 2.83078e-07 1 part in 8853757 103
x = e^-sqrt(sqrt(1-atan2(1)))+2
x = 2.50630008948185 = T + 8.94818e-08 1 part in 28009033 114
x = e^-(1/(e-atan2(3)))+2
x = 2.50630003893233 = T + 3.89323e-08 1 part in 64375799 114

Legend and Statistics: atan2(y,x) = Angle of ray from origin through point (y,x) pi = 3.14159... e = base of natural logarithms, 2.71828... cospi(X) = cos(pi * x) ln(x) = natural logarithm or log base e sinpi(X) = sin(pi * x) phi = the golden ratio, (1+sqrt(5))/2 tanpi(X) = tan(pi * x) sqrt(x) = square root Aⁿ√B = Ath root of B --LHS-- --RHS-- -Total- max complexity: 62 56 118 dead-ends: 802957 1210841 2013798 Time: 0.139 expressions: 55283 75051 130334 distinct: 33293 29176 62469 Memory: 4416KiB Total equations tested: 971356568 (9.714e+08)


For a more thorough search and many runtime options,

get the RIES source code and compile your own!

mrob.com/ries

  

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the Inverse Symbolic Calculator

  

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This page was written in the "embarrassingly readable" markup language RHTF, and was last updated on 2013 Feb 09. s.27